g^2-35g+34=0

Solution for g^2-35g+34=0 equation:

g^2-35g+34=0

a = 1; b = -35; c = +34;
Δ = b2-4ac
Δ = -352-4·1·34
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-33}{2*1}=\frac{2}{2}
=1
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+33}{2*1}=\frac{68}{2}
=34
$